cmd: exit: Fix return value propagation out of environment scripts
Make sure the 'exit' command as well as 'exit $val' command exits
from environment scripts immediately and propagates return value
out of those scripts fully. That means the following behavior is
expected:
"
=> setenv foo 'echo bar ; exit 1' ; run foo ; echo $?
bar
1
=> setenv foo 'echo bar ; exit 0' ; run foo ; echo $?
bar
0
=> setenv foo 'echo bar ; exit -2' ; run foo ; echo $?
bar
0
"
As well as the followin behavior:
"
=> setenv foo 'echo bar ; exit 3 ; echo fail'; run foo; echo $?
bar
3
=> setenv foo 'echo bar ; exit 1 ; echo fail'; run foo; echo $?
bar
1
=> setenv foo 'echo bar ; exit 0 ; echo fail'; run foo; echo $?
bar
0
=> setenv foo 'echo bar ; exit -1 ; echo fail'; run foo; echo $?
bar
0
=> setenv foo 'echo bar ; exit -2 ; echo fail'; run foo; echo $?
bar
0
=> setenv foo 'echo bar ; exit ; echo fail'; run foo; echo $?
bar
0
"
Fixes: 8c4e3b79bd ("cmd: exit: Fix return value")
Reviewed-by: Hector Palacios <hector.palacios@digi.com>
Signed-off-by: Marek Vasut <marex@denx.de>
This commit is contained in:
@@ -10,10 +10,13 @@
|
||||
static int do_exit(struct cmd_tbl *cmdtp, int flag, int argc,
|
||||
char *const argv[])
|
||||
{
|
||||
if (argc > 1)
|
||||
return dectoul(argv[1], NULL);
|
||||
int r;
|
||||
|
||||
return 0;
|
||||
r = 0;
|
||||
if (argc > 1)
|
||||
r = simple_strtoul(argv[1], NULL, 10);
|
||||
|
||||
return -r - 2;
|
||||
}
|
||||
|
||||
U_BOOT_CMD(
|
||||
|
||||
Reference in New Issue
Block a user