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dm: Drop the unused arg in uclass_find_device_by_seq()

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Now that there is only one sequence number (rather than both requested and
assigned ones) we can simplify this function. Also update its caller to
simplify the logic.

Signed-off-by: Simon Glass <sjg@chromium.org>
This commit is contained in:
Simon Glass
2020-12-16 21:20:29 -07:00
parent b5b11558bc
commit 991759196f
12 changed files with 64 additions and 94 deletions
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16
drivers/core/device.c
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@@ -647,15 +647,15 @@ int device_get_child_count(const struct udevice *parent)
return count;
}
int device_find_child_by_seq(const struct udevice *parent, int seq_or_req_seq,
bool find_req_seq, struct udevice **devp)
int device_find_child_by_seq(const struct udevice *parent, int seq,
struct udevice **devp)
{
struct udevice *dev;
*devp = NULL;
list_for_each_entry(dev, &parent->child_head, sibling_node) {
if (dev->sqq == seq_or_req_seq) {
if (dev->sqq == seq) {
*devp = dev;
return 0;
}
@@ -671,14 +671,8 @@ int device_get_child_by_seq(const struct udevice *parent, int seq,
int ret;
*devp = NULL;
ret = device_find_child_by_seq(parent, seq, false, &dev);
if (ret == -ENODEV) {
/*
* We didn't find it in probed devices. See if there is one
* that will request this seq if probed.
*/
ret = device_find_child_by_seq(parent, seq, true, &dev);
}
ret = device_find_child_by_seq(parent, seq, &dev);
return device_get_device_tail(dev, ret, devp);
}